Example 2.1.4 Disproof by Counterexample
Answers:
1. We need to find real numbers a and b such that b2 > a2 and b < a (b is not greater than a).
Counterexample : Let a = 3 and b = -4. Then a2 = 32 = 9 and b2 = (-4)2 = 16, and so b2 > a2 .
But b < a since -4 < 3.
2. We need to find real numbers x, y and z such that x > y and xz < yz (xz is not greater than yz).
Counterexample : Let x = 10, y = 8 and z = -3. Then x > y, since 10 > 8. But xz = 10 * (-3) = -30
and yz = 8 * (-3) = -24.
-30 < -24, and hence xz < yz.